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Math Domain A.1 : Topic 5
Apply laws of logarithm to real life situations
1 / 20
In population growth models, logarithms are mainly used to:
Reasoning: Logarithms help convert exponential relationships into simpler algebraic forms for solving unknowns.
2 / 20
If a quantity grows according to $N=N_0\times2^t$, which operation helps solve for $t$?
Reasoning: Taking logarithms allows the exponent $t$ to be brought down and solved.
3 / 20
Which real-life process is commonly modeled by exponential decay?
Reasoning: Radioactive substances decrease exponentially over time.
4 / 20
Sound intensity level is measured using:
Reasoning: Sound intensity is commonly expressed in decibels $(dB)$.
5 / 20
The decibel formula is:
Reasoning: Sound level is measured by
$L=10\log_{10}\left(\frac{I}{I_0}\right)$
6 / 20
Why are logarithms useful in radioactive decay?
Reasoning: Logarithms simplify exponential decay equations into easier linear relationships.
7 / 20
Which law explains $\log(ab)=\log(a)+\log(b)$ in real-life growth models?
Reasoning: Product law converts multiplication into addition.
$\log(ab)=\log(a)+\log(b)$
8 / 20
If a population becomes three times larger, the logarithmic expression becomes:
Reasoning: Product law states
9 / 20
In decay problems, taking logarithms is useful because it:
Reasoning: Logarithms transform exponential decay into linear form.
10 / 20
If the intensity ratio is $\frac{I_2}{I_1}=1000$, the decibel difference is:
Reasoning:
$L=10\log_{10}(1000)$
$=10\times3$
$=30,dB$
11 / 20
Which law is used when solving $\log(a^b)$ in growth models?
Reasoning: Power law states
$\log(a^b)=b\log(a)$
12 / 20
If sound level increases from $40,dB$ to $60,dB$, intensity increases by:
Reasoning: A difference of $20,dB$ corresponds to
$10^2=100$
times increase in intensity.
13 / 20
Which of the following best describes the use of logarithms in real life?
Reasoning: Logarithms are mainly used to simplify growth, decay and exponential models.
14 / 20
A radioactive substance halves every hour. Which mathematical form best represents it?
Reasoning: Repeated halving is an example of exponential decay.
15 / 20
Why are logarithms used in sound measurement?
Reasoning: Logarithmic scales make very large intensity ranges easier to handle.
16 / 20
If
then doubling intensity results in:
$10\log_{10}(2)\approx3,dB$
17 / 20
Which transformation is used to solve for time in exponential growth?
Reasoning: Logarithms bring the exponent (time variable) down for solving.
18 / 20
If two sounds differ by $10,dB$, the intensity ratio is:
$10\log_{10}\left(\frac{I_2}{I_1}\right)=10$
Therefore
$\frac{I_2}{I_1}=10$
19 / 20
Which law is applied when separating the logarithm of a quotient in decay analysis?
Reasoning: Quotient law states
$\log\left(\frac{a}{b}\right)=\log(a)-\log(b)$
20 / 20
In real-life modeling, logarithms are mainly used to:
Reasoning: Logarithms simplify growth, decay and sound-intensity calculations involving exponential change.
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