FBISE, NCP & NBF-aligned resources for Classes 9–12
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Math Chapter 3 : Test Yourself
1 / 11
Set builder form of $A - B$ is ________.
Reasoning: $A - B$ means elements in $A$ but not in $B$.
2 / 11
If $A \cup B = A$ and $A \cap B = B$, then ________.
Reasoning: $A \cup B = A$ $\Longrightarrow$ $B \subseteq A$, and $A \cap B = B$ confirms the same.
3 / 11
If $A \subset B$ then $A - B =$ ________.
Reasoning: If $A \subset B$, then all elements of $A$ are in $B$.So, nothing remains in $A - B$.
4 / 11
If $A - B = B - A = \phi$, then ________.
Reasoning: If $A - B = B - A = \phi$ $\Longrightarrow$ both sets have exactly same elements $\Longrightarrow$ $A = B$ $\Longrightarrow$ both are subsets of each other.
5 / 11
Set of common elements of $A$ and $A^{c}$ is ________ set.
Reasoning: $A \cap A^{c} =$ no common elements $\Longrightarrow$ empty (null) set.
6 / 11
Set of real numbers can be written in _________.
Reasoning: Real numbers are infinite $\Longrightarrow$ written in descriptive or set-builder form, not tabular.
7 / 11
If $R = \{(2,1)$, $(4,3)$, $(2,2)\}$, then Dom $R =$ ________.
Reasoning: Domain $=$ first elements of ordered pairs (no repetition).
8 / 11
If $R = \{(a,b)\ |\ a,\ \ b \in Z \land a + b = 0\}$, then ________.
Reasoning: For every integer $a$, $b = - \ a$ exists $\Longrightarrow$ both domain and range $=$ all integers.
9 / 11
If $R = \{(a,b)\ |\ a,\ \ b \in N \land a \times b = 12\}$ then tabular form of $R$ is:
Reasoning: All ordered pairs of natural numbers whose product is $12$.
10 / 11
If $n(A) = p$, then $n(A \times A) =$ ________.
Reasoning: $n(A \times A) = p \times p = p^{2}$
11 / 11
If $n(B) = t$, then number of binary relations in $B \times B$ is:
Reasoning: Total subsets of $B \times B$ $($size $t^{2})$ $\Longrightarrow$ Number of relations $= 2^{t^{2}}$
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