FBISE, NCP & NBF-aligned resources for Classes 9–12

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Math Chapter 6 : Topic 7

Bearing Problems

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A ship travels on bearing ${060}^{o}$. This means it is moving:

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A plane flies on bearing ${180}^{o}$. Its direction is:

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A bearing of ${090}^{o}$ corresponds to:

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A ship moves from $A$ to $B$ on bearing ${135}^{o}$. This direction lies in:

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If a person walks on bearing ${225}^{o}$, the direction is:

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A bearing of ${315}^{o}$ represents:

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Two points are $10 km$ apart. If the bearing from $A$ to $B$ is ${030}^{o}$, then the return bearing from $B$ to $A$ is:

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A boat travels on bearing ${120}^{o}$. It then turns ${90}^{o}$ clockwise. New bearing is:

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A bearing of ${000}^{o}$ means direction:

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A plane flies ${50}^{o}$ east of north. Its bearing is:

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A ship sails on bearing ${200}^{o}$. This is closest to:

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A bearing of ${270}^{o}$ is:

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If bearing from $A$ to $B$ is ${045}^{o}$, then $B$ to $A$ is:

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A person walks $10 km$ north then $10 km$ east. Final bearing from start to end is:

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Which bearing is exactly opposite to ${315}^{o}$?

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A plane moves on bearing ${090}^{o}$ then turns ${180}^{o}$. New direction is:

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A bearing increases in:

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A boat travels on bearing ${150}^{o}$ and returns directly. Return bearing is:

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Which bearing lies in North-West direction?

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A ship moves from $A$ to $B$ on ${090}^{o}$ and then $B$ to $C$ on ${180}^{o}$. Turn made is:

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If a bearing is ${001}^{o}$, direction is:

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A bearing of ${180}^{o}+{90}^{o}$ equals:

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A person moves $5 km$ on bearing ${060}^{o}$ then $5 km$ on ${240}^{o}$. Net displacement is:

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Which pair are perpendicular bearings?

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A bearing of ${360}^{o}$ is equivalent to:

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9th class objective books