FBISE, NCP & NBF-aligned resources for Classes 9–12
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Math Chapter 6 : Topic 4
Trig Identities
1 / 25
If $sin \theta=$ $\frac{3}{5} $, then $cos \theta$ is:
Reasoning: ${cos}^{2} \theta=1-{sin}^{2} \theta=1-$ $\frac{9}{25}$ $=$ $\frac{16}{25}$
2 / 25
Which identity is always true?
Reasoning: Fundamental identity.
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If $tan \theta=$ $\frac{5}{12} $, then $sin \theta$ is:
Reasoning: Triangle$ \Longrightarrow 5-12-13$
4 / 25
Simplify: $\frac{sin \theta}{cos \theta}$
Reasoning: Definition of tangent.
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Which expression equals 1?
Reasoning: Pythagorean identity.
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If $cos \theta=$ $\frac{8}{17} $, then $sin \theta$ is:
Reasoning: $8-15-17$ triangle.
7 / 25
Simplify: $\frac{1}{sin \theta}$
Reasoning: Definition of cosecant.
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If $tan \theta=1$, then $sin \theta=cos \theta$. This shows:
Reasoning: It shows a derived relation.
9 / 25
Simplify: $\frac{{sin}^{2} \theta}{1 - {cos}^{2} \theta}$
Reasoning: $1-{cos}^{2} \theta={sin}^{2} \theta$
10 / 25
If $sin \theta=$ $\frac{12}{13} $, then $tan \theta$ is:
Reasoning: $5-12-13$ triangle.
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Which identity is used to convert tangent into sine and cosine?
Reasoning: Direct relation.
12 / 25
Simplify: $\frac{1 - {cos}^{2} \theta}{{sin}^{2}\theta}$
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If $sin \theta=cos \theta$, then $\theta$ is:
Reasoning: Equal opposite and adjacent$ \Longrightarrow {45}^{o}$
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Simplify: $\frac{cos \theta}{sin \theta}$
Reasoning: Definition of cotangent.
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If $tan \theta=$ $\frac{3}{4} $, then $cos \theta$ is:
Reasoning: $3-4-5$ triangle.
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Which identity helps in proving ${sec}^{2} \theta-{tan}^{2} \theta=1$?
Reasoning: Rearranging gives required identity.
17 / 25
Simplify: $\frac{1}{cos \theta}$
Reasoning: Definition of secant.
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If $cos \theta=$ $\frac{5}{13} $, then $tan \theta$ is:
19 / 25
Simplify: $\frac{tan \theta}{sec \theta}$
Reasoning: $\frac{sin \theta / cos \theta}{1 / cos \theta}$ $=sin \theta$
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Which identity is used to eliminate sine in terms of cosine?
Reasoning: Rearranged gives ${sin}^{2} \theta=1-{cos}^{2} \theta$.
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If $tan \theta=1$, then $sec \theta$ is:
Reasoning: $\theta={45}^{o}$, $sec=\sqrt{2}$
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Simplify: $\frac{{sec}^{2} \theta - 1}{{tan}^{2} \theta}$
Reasoning: ${sec}^{2} \theta-1={tan}^{2} \theta$
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If $sin \theta=$ $\frac{8}{17} $, then $cos \theta$ is:
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Simplify: $\frac{1}{tan \theta}$
Reasoning: Reciprocal identity.
25 / 25
Which identity proves $\frac{1}{sin \theta}$ $=csc \theta $?
Reasoning: Reciprocal identities.
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