FBISE, NCP & NBF-aligned resources for Classes 9–12
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Math Chapter 4 : Topic 4
Algebraic Square Roots
1 / 20
The square root of $x^{2} + 6x + 9$ is:
Reasoning: $x^{2} + 6x + 9 = {(x + 3)}^{2}$, so its square root is $x + 3$.
2 / 20
Which expression is a perfect square?
Reasoning: $x^{2} + 4x + 4 = {(x + 2)}^{2}$, hence a perfect square.
3 / 20
Find $$.
Reasoning: $= \ \ .\ \ = 4x$
4 / 20
The square root of ${9a}^{2} + 6ab + b^{2}$ is:
Reasoning: It matches $3a + b^{2}$.
5 / 20
Which method is used to find square roots of algebraic expressions?
Reasoning: Division method is used for systematic extraction of square roots.
6 / 20
Find square root of $x^{2} - 10x + 25$.
Reasoning: $x^{2} - 10x\ + 25\ = (x - 5)^{2}$
7 / 20
Which expression is $NOT$ a perfect square?
Reasoning: Only $C$ cannot be expressed as a complete square.
8 / 20
Square root of ${25x}^{2} + 20x + 4$ is:
Reasoning: ${25x}^{2} + 20x + 4 = {(5x + 2)}^{2}$
9 / 20
The expression $x^{2} + 2xy + y^{2}$ is equal to:
Reasoning: It matches the identity ${(x + y)}^{2}$
10 / 20
Reasoning: $= 7ab$
11 / 20
Which step comes first in division method of square root?
Reasoning: Terms are grouped in pairs before extraction.
12 / 20
Square root of $x^{2} + 14x + 49$ is:
Reasoning: $x^{2} + 14x + 49 = {(x + 7)}^{2}$
13 / 20
Which is the correct factorization of $x^{2} - 2x + 1$?
Reasoning: It matches perfect square identity.
14 / 20
If $A = {(x + 4)}^{2}$, then $()$ is:
Reasoning: Square root removes square: $\ ^{2} = x + 4$
15 / 20
Which expression represents a perfect square trinomial?
Reasoning: $x^{2} + 6x + 9 = {(x + 3)}^{2}$
16 / 20
Square root of $36x^{2} - 12x + 1$ is:
Reasoning: ${(6x - 1)}^{2} = {36x}^{2} - 12x + 1$
17 / 20
Why is $x^{2} + 2x + 5$ not a perfect square?
Reasoning: It cannot be written in form ${(x + a)}^{2}$.
18 / 20
Square root of ${81a}^{2} + 18ab + b^{2}$:
Reasoning: $(9a + b)^{2}$
19 / 20
Which expression is a perfect square of a binomial?
Reasoning: It equals ${(x - 2)}^{2}$.
20 / 20
The square root of a product $a^{2\ }b^{2}$ is:
Reasoning: $= ab$
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