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Physics Chapter 8 : Topic 3
Ideal Gas Equation
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The equation of state for an ideal gas is:
Reasoning: The ideal gas equation relates pressure, volume, temperature, and amount of gas as $\mathbf{(PV = nRT)}$.
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In the equation $\mathbf{(PV = nRT)}$, the symbol $\mathbf{(n)}$ represents:
Reasoning: $\mathbf{(n)}$ is the amount of substance measured in moles.
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In the equation $\mathbf{(PV = NkT)}$, the symbol $\mathbf{(N)}$ represents:
Reasoning: $\mathbf{(N)}$ denotes the total number of molecules in the gas.
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The SI unit of pressure used in the ideal gas equation is:
Reasoning: $\mathbf{SI}$ units require pressure in pascals.
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The SI unit of volume in $\mathbf{(PV = nRT)}$ is:
Reasoning: $\mathbf{SI}$ unit of volume is cubic meter.
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If the temperature of an ideal gas doubles while pressure remains constant, the volume will:
Reasoning: From $\mathbf{V \propto T}$ when pressure is constant.
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For a fixed amount of gas at constant temperature, pressure is inversely proportional to:
Reasoning: Boyle’s law follows from $\mathbf{(PV = nRT)}$ when $\mathbf{(T)}$ and $\mathbf{(n)}$ are constant.
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Temperature in the ideal gas equation must be measured in:
Reasoning: Absolute temperature in Kelvin must be used.
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Which quantity remains constant for a fixed sample of gas?
Reasoning: The amount of gas remains fixed unless gas is added or removed.
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If volume decreases while temperature remains constant, pressure:
Reasoning: Pressure and volume are inversely related at constant temperature.
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The gas constant $\mathbf{(R)}$ has a value approximately equal to:
Reasoning: Universal gas constant $\mathbf{(R = 8.31)\ }\mathbf{J\ mol}^{\mathbf{- 1\ }}\mathbf{K}^{\mathbf{- 1}}$.
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The Boltzmann constant $\mathbf{(k)}$ is approximately:
Reasoning: Boltzmann constant links molecular-scale quantities with temperature.
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Which equation relates pressure and volume directly to the number of molecules?
Reasoning: $\mathbf{(N)}$ explicitly represents the number of molecules.
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One mole of any ideal gas contains:
Reasoning: One mole contains Avogadro’s number of molecules.
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The relationship between $\mathbf{(R)}$ and $\mathbf{(k)}$ is:
Reasoning: Universal gas constant equals Avogadro’s number multiplied by Boltzmann constant.
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An ideal gas occupies $\mathbf{2\ m}^{\mathbf{3}}$ at pressure $\mathbf{2 \times}\mathbf{10}^{\mathbf{5}}\mathbf{\ Pa}$. The product $\mathbf{(PV)}$ is:
Reasoning: $\mathbf{PV = (2 \times}\mathbf{10}^{\mathbf{5}}\mathbf{)(2) = 4 \times}\mathbf{10}^{\mathbf{5}}\mathbf{\ J}$
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If the number of moles is doubled while $\mathbf{(P)}$ and $\mathbf{(T)}$ remain constant, the volume:
Reasoning: From $\mathbf{V =}$ $\frac{\mathbf{nRT}}{\mathbf{P}}$, volume is proportional to moles. $\mathbf{\Longrightarrow}$ $\mathbf{V \propto n}$
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Which variable must never be expressed in Celsius in gas law calculations?
Reasoning: Kelvin scale is required for all gas law calculations.
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A gas at $\mathbf{300\ K}$ is heated to $\mathbf{600\ K}$ at constant volume. The pressure becomes:
Reasoning: $\mathbf{P \propto T}$ at constant volume.
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The equation $\mathbf{(PV = NkT)}$ shows that pressure depends directly on:
Reasoning: Pressure increases with both molecular number and temperature.
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An ideal gas has pressure $\mathbf{1 \times}\mathbf{10}^{\mathbf{5}}\mathbf{\ Pa}$ and volume $\mathbf{0.03\ m}^{\mathbf{3}}$. Calculate $\mathbf{(PV)}$.
Reasoning: $\mathbf{PV = (1 \times}\mathbf{10}^{\mathbf{5}}\mathbf{)(0.03) = 3000\ J}$
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Which assumption is made for an ideal gas?
Reasoning: Ideal gases are assumed to have negligible intermolecular forces.
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If temperature decreases while volume remains constant, pressure:
Reasoning: $\mathbf{P \propto T}$ when volume is constant.
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Which graph is a straight line for an ideal gas at constant pressure?
Reasoning: Charles’s law shows $\mathbf{V \propto T}$.
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The product $\mathbf{(PV)}$ for an ideal gas is proportional to:
Reasoning: $\mathbf{(PV = nRT)}$, therefore $\mathbf{PV \propto nT}$.
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If the number of molecules doubles at constant volume and temperature, pressure:
Reasoning: From $\mathbf{(PV = NkT)}$, pressure is directly proportional to $\mathbf{(N)}$.
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Which quantity distinguishes $\mathbf{(PV = nRT)}$ from $\mathbf{(PV = NkT)}$?
Reasoning: One uses moles $\mathbf{(n)}$, the other uses molecules $\mathbf{(N)}$.
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Why is Kelvin scale used in gas equations?
Reasoning: Kelvin is the absolute thermodynamic temperature scale.
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A gas occupies $\mathbf{1\ m}^{\mathbf{3}}$ at $\mathbf{300\ K}$. At constant pressure, its volume at $\mathbf{600\ K}$ is:
Reasoning: Volume is directly proportional to temperature.
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The quantity $\mathbf{(NkT)}$ represents:
Reasoning: According to $\mathbf{(PV = NkT)}$, $\mathbf{(NkT)}$ equals $\mathbf{(PV)}$.
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If pressure and temperature are constant, volume is directly proportional to:
Reasoning: More molecules require larger volume at fixed pressure and temperature.
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Which law can be derived from $\mathbf{(PV = nRT)}$ when volume is constant?
Reasoning: With constant volume, pressure varies directly with temperature.
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A gas sample contains twice as many molecules as another sample at the same temperature and volume. Its pressure is:
Reasoning: $\mathbf{P \propto N}$ when $\mathbf{V}$ and $\mathbf{T}$ are constant.
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In $\mathbf{PV = nRT}$, if $\mathbf{P}$, $\mathbf{V}$, and $\mathbf{T}$ are known, one can determine:
Reasoning: Rearranging gives $\mathbf{n =}$ $\frac{\mathbf{PV}}{\mathbf{RT}}\mathbf{\ }$.
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The ideal gas equation combines:
Reasoning: The ideal gas equation unifies the basic gas laws.
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A gas occupies $\mathbf{0.5\ m}^{\mathbf{3}}$ at $\mathbf{200\ K}$. At constant pressure, what is its volume at $\mathbf{400\ K}$?
Reasoning: Doubling temperature doubles volume.
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If temperature increases by $\mathbf{50\%}$ at constant volume, pressure:
Reasoning: Pressure is directly proportional to temperature. $\mathbf{\Longrightarrow}$ $\mathbf{P \propto T}$
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Which quantity remains unchanged in the equation $\mathbf{(PV = nRT)}$ for a sealed container?
Reasoning: In a sealed container, no gas enters or leaves.
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The equation $\mathbf{(PV = NkT)}$ is particularly useful because it:
Reasoning: It links pressure and volume to the actual number of molecules.
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