FBISE, NCP & NBF-aligned resources for Classes 9–12
Browse by Class
Browse by Type
Physics Chapter 5 : Topic 1
Kinetic Energy
1 / 36
The energy possessed by a body due to its motion is called:
Reasoning: Kinetic energy is the energy associated with the motion of an object.
2 / 36
Kinetic energy of an object depends on:
Reasoning: The formula $\mathbf{K\ .E\ =}$ $\frac{\mathbf{1}}{\mathbf{2}}\mathbf{m}\mathbf{v}^{\mathbf{2}}$ shows dependence on both mass and velocity.
3 / 36
The SI unit of kinetic energy is:
Reasoning: Energy is measured in joules $\mathbf{(}$J$\mathbf{)}$.
4 / 36
A stationary object has kinetic energy equal to:
Reasoning: $\mathbf{K\ .E =}$ $\frac{\mathbf{1}}{\mathbf{2}}\mathbf{m}\mathbf{v}^{\mathbf{2}}$ $\mathbf{\Longrightarrow}$ When $\mathbf{v = 0}$, kinetic energy is zero.
5 / 36
Kinetic energy is a:
Reasoning: Energy has magnitude only, not direction.
6 / 36
The equation of motion used to derive kinetic energy is:
Reasoning: The relation between velocity, acceleration, and displacement is used.
7 / 36
The work done by a constant force is:
Reasoning: Work is force multiplied by displacement.
8 / 36
In the derivation of kinetic energy, force is replaced using:
Reasoning: $\mathbf{F = ma}$ is used.
9 / 36
The work done on an object becomes its:
Reasoning: Work done changes the kinetic energy of an object.
10 / 36
During derivation of kinetic energy, acceleration is eliminated using:
Reasoning: This equation connects acceleration with velocity and displacement.
11 / 36
The work-energy theorem states that:
Reasoning: $\mathbf{W = \Delta\ }\mathbf{K\ .E}$
12 / 36
The final expression obtained after deriving kinetic energy is:
Reasoning: Kinetic energy depends on half the product of mass and square of velocity.
13 / 36
In the derivation of kinetic energy, if initial velocity is zero, then:
Reasoning: An object starting from rest has initial velocity zero.
14 / 36
For an object starting from rest, the equation: $\mathbf{v}^{\mathbf{2}}\mathbf{=}\mathbf{u}^{\mathbf{2}}\mathbf{+ 2as}$
Reasoning: Since $\mathbf{u = 0}$ $\mathbf{\Longrightarrow}$ $\mathbf{v}^{\mathbf{2}}\mathbf{= 2as}$
15 / 36
The expression for work done using Newton’s second law is:
Reasoning: $\mathbf{W}\mathbf{=}\mathbf{Fs}$ and $\mathbf{F}\mathbf{=}\mathbf{ma}$ $\mathbf{\Longrightarrow}$ Therefore, $\mathbf{W}\mathbf{=}\mathbf{mas}$
16 / 36
Substituting $\mathbf{as =}$ $\frac{\mathbf{v}^{\mathbf{2}}}{\mathbf{2}}$ into work equation gives:
Reasoning: $\mathbf{W = m}\left( \mathbf{as} \right)$ ; $\mathbf{W =}$ $\frac{\mathbf{1}}{\mathbf{2}}\mathbf{m}\mathbf{v}^{\mathbf{2}}$
17 / 36
If the mass of an object is doubled while velocity remains constant, kinetic energy becomes:
Reasoning: $\mathbf{K\ .E}\mathbf{\propto m}$
18 / 36
If velocity of an object is doubled, kinetic energy becomes:
Reasoning: $\mathbf{K\ .E}\mathbf{\propto}\mathbf{v}^{\mathbf{2}}$
19 / 36
A truck and a car moving with the same velocity have different kinetic energies because:
Reasoning: Kinetic energy depends directly on mass.
20 / 36
A small increase in velocity causes a large increase in kinetic energy because:
Reasoning: Velocity is squared in the formula.
21 / 36
A$\mathbf{\ }\mathbf{2\ kg\ }$object moving with velocity $\mathbf{5\ m/s}$ has kinetic energy:
Reasoning: $\mathbf{K\ .E}\mathbf{=}$ $\frac{\mathbf{1}}{\mathbf{2}}\mathbf{m}\mathbf{v}^{\mathbf{2}}\mathbf{=}\frac{\mathbf{1}}{\mathbf{2}}\mathbf{(2)(25) = 25\ J}$
22 / 36
A car of mass $\mathbf{1000\ kg}$ moves at $\mathbf{20\ m/s}$. Its kinetic energy is:
Reasoning: $\mathbf{K\ .E}\mathbf{=}$ $\frac{\mathbf{1}}{\mathbf{2}}\mathbf{m}\mathbf{v}^{\mathbf{2}}\mathbf{=}\frac{\mathbf{1}}{\mathbf{2}}\mathbf{(1000)}\mathbf{(20)}^{\mathbf{2}}\mathbf{= 200000\ J}$
23 / 36
A body has kinetic energy $\mathbf{400\ J}$ and mass $\mathbf{8\ kg}$. Its velocity is:
Reasoning: $\mathbf{400 =}$ $\frac{\mathbf{1}}{\mathbf{2}}\mathbf{(8)\ }\mathbf{v}^{\mathbf{2}}$ $\mathbf{\Longrightarrow}$ $\mathbf{v}^{\mathbf{2}}\mathbf{= 100}$ $\mathbf{\Longrightarrow}$ $\mathbf{v = 10\ m/s}$
24 / 36
Two objects have equal kinetic energy. The heavier object will have:
Reasoning: For equal $\mathbf{K\ .E}$ $\mathbf{\Longrightarrow}$ $\mathbf{K\ .E}\mathbf{=}$ $\frac{\mathbf{1}}{\mathbf{2}}\mathbf{m}\mathbf{v}^{\mathbf{2}}$ ; Greater mass requires smaller velocity. The heavier object will have more momentum, less velocity, and a greater magnitude of momentum than the lighter object.
25 / 36
If the velocity of a body becomes three times, its kinetic energy becomes:
Reasoning: $\mathbf{K\ .E}\mathbf{\propto}\mathbf{v}^{\mathbf{2}}$ $\mathbf{\Longrightarrow}$ $\mathbf{3}^{\mathbf{2}}\mathbf{= 9}$
26 / 36
A bullet has large kinetic energy because:
Reasoning: High velocity greatly increases kinetic energy.
27 / 36
A loaded truck moving slowly may have large kinetic energy because:
Reasoning: $\mathbf{K\ .E}$ depends directly on mass.
28 / 36
When brakes are applied to a moving car, its kinetic energy is converted into:
Reasoning: Friction converts kinetic energy into thermal energy.
29 / 36
A moving object has positive kinetic energy because:
Reasoning: Mass and squared velocity give positive energy.
30 / 36
Kinetic energy cannot be negative because:
Reasoning: $\mathbf{v}^{\mathbf{2}}$ is always positive.
31 / 36
A body moving with zero acceleration can still have kinetic energy if:
Reasoning: Constant velocity still means motion and kinetic energy.
32 / 36
An object moving at constant velocity has:
Reasoning: Constant velocity means constant $\mathbf{K\ .E}$.
33 / 36
The dimensions of kinetic energy are:
Reasoning: $\mathbf{K\ .E}\mathbf{=}$ $\frac{\mathbf{1}}{\mathbf{2}}\mathbf{m}\mathbf{v}^{\mathbf{2}}$ ; Dimensions: $\mathbf{M}\mathbf{(L\ /\ T)}^{\mathbf{2}}\mathbf{= M\ }\mathbf{L}^{\mathbf{2\ }}\mathbf{T}^{\mathbf{- 2}}$
34 / 36
The slope of a velocity-time graph represents:
Reasoning: Acceleration is the rate of change of velocity.
35 / 36
The derivation of kinetic energy assumes:
Reasoning: Equations of motion are valid for constant acceleration.
36 / 36
Which statement is correct?
Reasoning: $\mathbf{K\ .E}\mathbf{=}$ $\frac{\mathbf{1}}{\mathbf{2}}\mathbf{m}\mathbf{v}^{\mathbf{2}}$ shows quadratic dependence on velocity.
Your score is
Restart quiz
