FBISE, NCP & NBF-aligned resources for Classes 9–12
Browse by Class
Browse by Type
Physics Chapter 10 : Topic 4
Motion of Charged Particles in Electric Fields
1 / 30
A charged particle placed in a uniform electric field experiences:
Reasoning: In a uniform electric field, field strength is constant, so $\mathbf{(F = qE)}$ gives a constant force.
2 / 30
The force acting on a charged particle in an electric field is given by:
Reasoning: The electric force is directly proportional to charge and electric field strength.
3 / 30
A positive charge placed in a uniform electric field will accelerate:
Reasoning: A positive charge experiences force in the same direction as the electric field.
4 / 30
A negative charge placed in a uniform electric field will accelerate:
Reasoning: Negative charges experience force opposite to the direction of the electric field.
5 / 30
The acceleration of a charged particle in a uniform electric field depends on:
Reasoning: From: $\mathbf{F = qE}$ and $\mathbf{F = ma}$ $\mathbf{\Longrightarrow}$ $\mathbf{a =}$ $\frac{\mathbf{qE}}{\mathbf{m}}$Acceleration depends on charge, field strength, and mass.
6 / 30
A charged particle moving in a uniform electric field experiences constant:
Reasoning: Constant force produces constant acceleration.
7 / 30
If the charge of a particle is doubled while mass remains the same, its acceleration in a uniform electric field:
Reasoning: $\mathbf{a =}$ $\frac{\mathbf{qE}}{\mathbf{m}}$ ; Acceleration is directly proportional to charge.
8 / 30
A proton and an electron are placed in the same uniform electric field. Which experiences greater acceleration?
Reasoning: Both have equal charge magnitude, but electron has much smaller mass, so its acceleration is greater.
9 / 30
A charged particle initially at rest in a uniform electric field will:
Reasoning: The electric force causes acceleration. Direction depends on charge sign.
10 / 30
The motion of a charged particle in a uniform electric field is similar to:
Reasoning: Both involve constant acceleration due to a uniform force.
11 / 30
If the mass of a charged particle is doubled while charge and field remain constant, acceleration:
Reasoning: $\mathbf{a =}$ $\frac{\mathbf{qE}}{\mathbf{m}}$ ; Acceleration is inversely proportional to mass.
12 / 30
A positively charged particle enters a uniform electric field with velocity in the same direction as the field. Its speed will:
Reasoning: Electric force acts in the direction of motion, increasing kinetic energy.
13 / 30
A positive charge moving opposite to the direction of an electric field will:
Reasoning: Electric force acts opposite to its motion, reducing kinetic energy.
14 / 30
When a charged particle moves through a uniform electric field, the work done by the field changes:
Reasoning: Work done by electric force changes the kinetic energy of the particle.
15 / 30
A particle with charge $\mathbf{(2\ C)}$ is placed in an electric field of $\mathbf{(5\ N/C)}$. The force acting on it is:
Reasoning: $\mathbf{F = qE = (2)(5) = 10\ N}$
16 / 30
A charged particle experiences a force of $\mathbf{(12\ N)}$ in an electric field of $\mathbf{(3\ N/C)}$. Its charge is:
Reasoning: $\mathbf{q =}$ $\frac{\mathbf{F}}{\mathbf{E}}\mathbf{=}\frac{\mathbf{12}}{\mathbf{3}}\mathbf{= 4\ C}$
17 / 30
A charged particle moving in a uniform electric field gains energy because:
Reasoning: Work done by electric force changes electrical potential energy into kinetic energy.
18 / 30
If the electric field strength becomes zero, the acceleration of a charged particle becomes:
Reasoning: $\mathbf{a =}$ $\frac{\mathbf{qE}}{\mathbf{m}}$ $\mathbf{\Longrightarrow}$ If $\mathbf{(E = 0)}$, acceleration is zero.
19 / 30
A charged particle entering a uniform electric field perpendicular to the field direction follows:
Reasoning: Constant acceleration perpendicular to initial velocity produces a parabolic trajectory.
20 / 30
In a uniform electric field, a charged particle moving along the field direction has:
Reasoning: The electric force remains constant, producing constant acceleration.
21 / 30
Two charged particles with the same charge are placed in the same electric field. The one with smaller mass will:
Reasoning: Since $\mathbf{a =}$ $\frac{\mathbf{qE}}{\mathbf{m}}$, smaller mass gives greater acceleration.
22 / 30
The acceleration of a charged particle in a uniform electric field is independent of:
Reasoning: In a uniform field, acceleration is constant and does not depend on position.
23 / 30
A proton between two charged parallel plates moves:
Reasoning: A proton is positively charged and moves in the direction of electric field, toward the negative plate.
24 / 30
An electron placed between two charged parallel plates moves:
Reasoning: Electrons are negatively charged and are attracted toward the positive plate.
25 / 30
A charged particle moving in a uniform electric field has constant acceleration because:
Reasoning: Uniform field produces constant force, which produces constant acceleration.
26 / 30
If the electric field strength is increased four times, acceleration of a charged particle becomes:
Reasoning: $\mathbf{a =}$ $\frac{\mathbf{qE}}{\mathbf{m}}$ ; Acceleration is directly proportional to electric field strength.
27 / 30
A charged particle enters a uniform electric field with no initial velocity. Its velocity after some time will:
Reasoning: Constant acceleration causes velocity to increase uniformly.
28 / 30
Which factor determines whether a charged particle accelerates along or opposite to the field?
Reasoning: Positive charges accelerate along the field; negative charges opposite.
29 / 30
A charged particle moving through a uniform electric field does not experience acceleration if:
Reasoning: An uncharged particle experiences no electric force.
30 / 30
A charged particle moving parallel to electric field lines experiences:
Reasoning: The electric force acts along the field direction for a positive charge moving parallel to field lines.
Your score is
Restart quiz
