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Physics Chapter 14 : Topic 9
Quark Changes in Beta Decay
1 / 30
During $\mathbf{\beta}^{\mathbf{-}}$ decay, which quark transformation takes place?
Reasoning: In $\mathbf{\beta}^{\mathbf{-}}$ decay, a down quark changes into an up quark, causing a neutron to become a proton.
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A neutron changes into a proton during $\mathbf{\beta}^{\mathbf{-}}$ decay because:
Reasoning: A neutron $\mathbf{(udd)}$ becomes a proton $\mathbf{(uud)}$ when one down quark converts into an up quark.
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The quark composition of a neutron before $\mathbf{\beta}^{\mathbf{-}}$ decay is:
Reasoning: A neutron consists of one up quark and two down quarks.
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The quark composition of a proton after $\mathbf{\beta}^{\mathbf{-}}$ decay is:
Reasoning: After one down quark changes into an up quark, the neutron becomes $\mathbf{uud}$, which is a proton.
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Which equation correctly represents the quark change in $\mathbf{\beta}^{\mathbf{-}}$ decay?
Reasoning: A down quark changes into an up quark while producing an electron and an electron antineutrino.
6 / 30
In $\mathbf{\beta}^{\mathbf{-}}$ decay, the emitted beta particle is produced when:
Reasoning: The $\mathbf{d\ }\overset{\mathbf{\ \ \ \ \ \ \ \ \ \ \ }}{\rightarrow}\mathbf{\ u}$ transformation inside the neutron results in emission of an electron and antineutrino.
7 / 30
The quark-level process responsible for $\mathbf{\beta}^{\mathbf{+}}$ decay is:
Reasoning: In $\mathbf{\beta}^{\mathbf{+}}$ decay, an up quark changes into a down quark.
8 / 30
During $\mathbf{\beta}^{\mathbf{+}}$ decay, a proton changes into:
Reasoning: A proton $\mathbf{(uud)}$ becomes a neutron $\mathbf{(udd)}$ when one up quark changes into a down quark.
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The quark composition of a proton before $\mathbf{\beta}^{\mathbf{+}}$ decay is:
Reasoning: A proton consists of two up quarks and one down quark.
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The quark composition of a neutron after $\mathbf{\beta}^{\mathbf{+}}$ decay is:
Reasoning: $\mathbf{\beta}^{\mathbf{+}}$ decay changes one up quark into a down quark, producing a neutron.
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Which equation represents $\mathbf{\beta}^{\mathbf{+}}$ decay at the quark level?
Reasoning: An up quark changes into a down quark, emitting a positron and electron neutrino.
12 / 30
In $\mathbf{\beta}^{\mathbf{+}}$ decay, the emitted particle is:
Reasoning: $\mathbf{\beta}^{\mathbf{+}}$ decay produces a positron along with an electron neutrino.
13 / 30
Which transformation increases the atomic number of a nucleus?
Reasoning: In $\mathbf{\beta}^{\mathbf{-}}$ decay, a neutron becomes a proton, increasing the number of protons.
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Which transformation decreases the atomic number of a nucleus?
Reasoning: $\mathbf{\beta}^{\mathbf{+}}$ decay converts a proton into a neutron, reducing the proton number.
15 / 30
A neutron has composition $\mathbf{udd}$. After $\mathbf{\beta ⁻}$ decay, its composition becomes:
Reasoning: One down quark changes into an up quark: $\mathbf{udd\ }\overset{\mathbf{\ \ \ \ \ \ \ \ \ \ \ }}{\rightarrow}\mathbf{\ uud}$
16 / 30
A proton has composition $\mathbf{uud}$. After $\mathbf{\beta}^{\mathbf{+}}$ decay, its composition becomes:
Reasoning: One up quark changes into a down quark: $\mathbf{uud\ }\overset{\mathbf{\ \ \ \ \ \ \ \ \ \ \ }}{\rightarrow}\mathbf{\ udd}$
17 / 30
Which statement correctly compares $\mathbf{\beta}^{\mathbf{-}}$ and $\mathbf{\beta}^{\mathbf{+}}$ decay?
Reasoning: $\mathbf{\beta}^{\mathbf{-}}$ converts a down quark into an up quark, while $\mathbf{\beta}^{\mathbf{+}}$ does the reverse.
18 / 30
The charge change during $\mathbf{\beta}^{\mathbf{-}}$ decay occurs because:
Reasoning: Changing $\mathbf{d\ ( - \ 1/3\ e)}$ into $\mathbf{u\ ( + \ 2/3\ e)}$ increases the charge by $\mathbf{+ e}$.
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Which decay changes a baryon from $\mathbf{uud}$ to $\mathbf{udd}$?
Reasoning: $\mathbf{\beta}^{\mathbf{+}}$ decay changes one up quark into a down quark.
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Which decay changes a baryon from $\mathbf{udd}$ to $\mathbf{uud}$?
Reasoning: $\mathbf{\beta}^{\mathbf{-}}$ decay changes a down quark into an up quark.
21 / 30
The charge change during $\mathbf{\beta}^{\mathbf{+}}$ decay occurs because:
Reasoning: $\mathbf{u\ ( + \ 2/3\ e)}$ changes into $\mathbf{d\ ( - \ 1/3\ e)}$, reducing charge by one elementary charge.
22 / 30
In $\mathbf{\beta}^{\mathbf{-}}$ decay, the particle emitted along with the electron is:
Reasoning: The quark change $\mathbf{d\ }\overset{\mathbf{\ \ \ \ \ \ \ \ \ \ \ }}{\rightarrow}\mathbf{\ u}$ produces an electron and an electron antineutrino.
23 / 30
In $\mathbf{\beta}^{\mathbf{+}}$ decay, the particle emitted along with the positron is:
Reasoning: $\mathbf{\beta}^{\mathbf{+}}$ decay produces an electron neutrino.
24 / 30
Which quark transformation occurs inside a neutron during $\mathbf{\beta}^{\mathbf{-}}$ decay?
Reasoning: A neutron contains two down quarks, and one changes into an up quark.
25 / 30
Which particle changes into another during $\mathbf{\beta}^{\mathbf{+}}$ decay?
Reasoning: In $\mathbf{\beta}^{\mathbf{+}}$ decay, a proton becomes a neutron due to $\mathbf{u\ }\overset{\mathbf{\ \ \ \ \ \ \ \ \ \ \ }}{\rightarrow}\mathbf{\ d}$ transformation.
26 / 30
The quark process $\mathbf{d}\mathbf{\ }\overset{\mathbf{\ \ \ \ \ \ \ \ \ \ \ }}{\rightarrow}\mathbf{\ }\mathbf{u}$ increases the particle charge by:
Reasoning: Charge changes from $\mathbf{- \ 1/3e}$ to $\mathbf{+ \ 2/3\ e}$, giving an increase of $\mathbf{+ \ e}$.
27 / 30
The quark process $\mathbf{u\ }\overset{\mathbf{\ \ \ \ \ \ \ \ \ \ \ }}{\rightarrow}\mathbf{\ d}$ decreases the particle charge by:
Reasoning: Charge changes from $\mathbf{+ \ 2/3\ e}$ to $\mathbf{- \ 1/3\ e}$, a decrease of one elementary charge.
28 / 30
A proton undergoing $\mathbf{\beta}^{\mathbf{+}}$ decay will have its quark content changed from:
Reasoning: One up quark converts into a down quark.
29 / 30
A neutron undergoing $\mathbf{\beta}^{\mathbf{-}}$ decay will have its quark content changed from:
Reasoning: One down quark converts into an up quark.
30 / 30
The fundamental interaction responsible for quark changes in beta decay is:
Reasoning: Quark transformations such as $\mathbf{d\ }\overset{\mathbf{\ \ \ \ \ \ \ \ \ \ }}{\rightarrow}\mathbf{\ u}$ and $\mathbf{u\ }\overset{\mathbf{\ \ \ \ \ \ \ \ \ \ }}{\rightarrow}\mathbf{\ d}$ occur through the weak nuclear force.
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