FBISE, NCP & NBF-aligned resources for Classes 9–12
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Physics Chapter 11 : Topic 5
Light-Dependent Resistor (LDR)
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A light-dependent resistor $\mathbf{(LDR)}$ is a device whose resistance changes with:
Reasoning: An $\mathbf{LDR}$ is a light-sensitive resistor whose resistance depends on the intensity of incident light.
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When the intensity of light falling on an $\mathbf{LDR}$ increases, its resistance:
Reasoning: More light produces more charge carriers in the $\mathbf{LDR}$ material, reducing its resistance.
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An $\mathbf{LDR}$ is commonly made from materials that are:
Reasoning: $\mathbf{LDRs}$ use semiconductor materials whose conductivity changes with light.
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In darkness, an$\mathbf{\ }\mathbf{LDR}$ usually has:
Reasoning: In the absence of light, fewer charge carriers are available, so resistance is high.
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A student covers an$\mathbf{\ }\mathbf{LDR}$ with a dark cloth. The resistance of the $\mathbf{LDR}$ will:
Reasoning: Blocking light reduces the number of charge carriers, increasing resistance.
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Which change will cause the current through an $\mathbf{LDR}$ circuit to increase (assuming constant voltage)?
Reasoning: Increased light intensity lowers $\mathbf{LDR}$ resistance, causing current to increase.
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Which graph correctly represents the relationship between light intensity and $\mathbf{LDR}$ resistance?
Reasoning: $\mathbf{LDR}$ resistance decreases when the intensity of incident light increases.
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The working principle of an $\mathbf{LDR}$ is based on:
Reasoning: Light energy creates additional charge carriers in the semiconductor material.
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An $\mathbf{LDR}$ is placed near a bright lamp. Compared with its value in darkness, its resistance will be:
Reasoning: Bright light increases conductivity and decreases resistance.
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Which device commonly uses an $\mathbf{LDR}$?
Reasoning: Street lights use $\mathbf{LDR}$ to detect day and night by sensing light intensity.
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In an automatic lighting system, an $\mathbf{LDR}$ switches lights $\mathbf{ON}$ at night because:
Reasoning: Darkness increases $\mathbf{LDR}$ resistance, which can trigger the switching circuit.
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Increasing the intensity of light on an $\mathbf{LDR}$ causes:
Reasoning: Light energy frees more charge carriers in the semiconductor.
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The resistance of an $\mathbf{LDR}$ is highest when it is:
Reasoning: Darkness provides minimum charge carriers, producing maximum resistance.
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If the resistance of an $\mathbf{\ }\mathbf{LDR\ }$ decreases due to increased light intensity, its conductivity:
Reasoning: Conductivity is inversely related to resistance.
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An $\mathbf{LDR}$ and a fixed resistor are connected in a voltage divider circuit. Increasing light intensity on the $\mathbf{LDR}$ will mainly change:
Reasoning: Changing $\mathbf{LDR}$ resistance changes the voltage division ratio.
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Which statement about an $\mathbf{LDR}$ is correct?
Reasoning: This is the defining property of an $\mathbf{LDR}$.
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Two identical $\mathbf{LDRs}$ are placed under different light conditions. $\mathbf{LDR\ A}$ is under bright light and $\mathbf{LDR\ B}$ is in darkness. Which is true?
Reasoning: Darkness increases$\ \ \mathbf{LDR\ \ }$resistance, while bright light decreases it.
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A student wants an $\mathbf{LDR}$ to detect small changes in light intensity. The best condition is:
Reasoning: An $\mathbf{LDR}$ is useful when changes in light produce measurable resistance changes.
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When light intensity increases on an $\mathbf{LDR}$, the number of free electrons:
Reasoning: Absorbed light energy releases more charge carriers.
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An $\mathbf{LDR}$ differs from an ordinary resistor because:
Reasoning: The unique feature of an $\mathbf{LDR}$ is its light-dependent resistance.
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A circuit containing an $\mathbf{LDR}$ is placed from daytime into darkness. The current in the circuit will generally:
Reasoning: Darkness increases $\mathbf{LDR}$ resistance, reducing current for a fixed voltage.
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The main purpose of using an $\mathbf{LDR}$ in electronic circuits is to:
Reasoning: $\mathbf{LDRs}$ act as sensors for measuring light intensity.
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A bright flashlight is directed at an $\mathbf{LDR}$. Which combination is correct?
Reasoning: Increased light intensity reduces $\mathbf{LDR}$ resistance.
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If the light intensity falling on an $\mathbf{LDR}$ is reduced, the resistance:
Reasoning: Less light produces fewer free charge carriers, increasing resistance.
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In an $\mathbf{LDR}$, light energy affects resistance by changing the:
Reasoning: Light increases charge carriers in the semiconductor, lowering resistance.
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An $\mathbf{LDR}$ is most suitable as a sensor in:
Reasoning: $\mathbf{LDRs}$ are designed to respond to variations in light intensity.
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If the resistance of an $\mathbf{LDR}$ decreases from $\mathbf{10\ k\Omega}$ to $\mathbf{1\ k\Omega}$, this indicates:
Reasoning: Lower resistance indicates stronger illumination.
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Which factor does NOT directly control the resistance of an $\mathbf{LDR}$?
Reasoning: External wire length does not determine $\mathbf{LDR}$ resistance.
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The relationship between light intensity and resistance of an $\mathbf{LDR}$ is generally:
Reasoning: As light intensity increases, resistance decreases.
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A student observes that an$\mathbf{\ \ }\mathbf{LDR\ }\mathbf{\ }$has a very high resistance. The most likely condition is:
Reasoning: $\mathbf{LDR}$ resistance is maximum in low-light conditions.
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In a security system, an $\mathbf{LDR}$ detects when a beam of light is interrupted. When the beam is blocked, the $\mathbf{LDR}$ resistance:
Reasoning: Blocking light reduces charge carriers, increasing resistance.
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The sensitivity of an$\mathbf{\ }\mathbf{LDR\ }$refers to its ability to:
Reasoning: Sensitivity describes how effectively resistance changes with light level.
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Which statement best explains why $\mathbf{LDRs}$ are called photo-resistors?
Reasoning: “Photo” refers to light, and resistance changes due to illumination.
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A decrease in $\mathbf{LDR}$ resistance due to light exposure results in:
Reasoning: Lower resistance means the material conducts electricity more easily.
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Which graph would show the correct behavior of an $\mathbf{LDR}$?
Reasoning: An$\ \mathbf{LDR}$ has lower resistance under stronger illumination.
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