FBISE, NCP & NBF-aligned resources for Classes 9–12

/40

Physics Chapter 8 : Topic 6

Work Done by a Gas

1 / 40

The work done when a gas expands at constant pressure is given by:

2 / 40

In the equation $\mathbf{W = p\mathrm{\Delta}V}$, the symbol $\mathbf{\mathrm{\Delta}V}$ represents:

3 / 40

The SI unit of work done by a gas is:

4 / 40

The SI unit of pressure in $\mathbf{W = p\mathrm{\Delta}V}$ is:

5 / 40

A gas expands against a constant pressure. The work done by the gas is:

6 / 40

If a gas is compressed at constant pressure, the work done by the gas is:

7 / 40

A gas expands from $\mathbf{2\ m}^{\mathbf{3}}$ to $\mathbf{5\ m}^{\mathbf{3}}$ at a pressure of $\mathbf{1000\ Pa}$. The work done is:

8 / 40

A gas expands by $\mathbf{0.02\ m}^{\mathbf{3}}$ against a pressure of $\mathbf{5 \times}\mathbf{10}^{\mathbf{4}}\mathbf{\ Pa}$. Work done is:

9 / 40

If there is no change in volume of a gas, the work done is:

10 / 40

The work done by a gas during expansion represents:

11 / 40

The area under a pressure-volume graph represents:

12 / 40

On a pressure-volume graph, constant pressure is represented by:

13 / 40

For a gas expanding at constant pressure, increasing the volume change will:

14 / 40

If pressure is doubled while volume change remains constant, work done:

15 / 40

A gas expands from $\mathbf{1\ m}^{\mathbf{3}}$ to $\mathbf{4\ m}^{\mathbf{3}}$ at $\mathbf{(2000\ Pa)}$. The work done is:

16 / 40

Which condition is necessary for using $\mathbf{W = p\mathrm{\Delta}V}$?

17 / 40

During expansion of a gas, the surroundings:

18 / 40

A gas does $\mathbf{500\ J}$ of work while expanding at constant pressure of $\mathbf{2500\ Pa}$. The change in volume is:

19 / 40

If a gas is compressed, the final volume is:

20 / 40

The equation $\mathbf{W = p\mathrm{\Delta}V}$ is derived from:

21 / 40

Pressure is defined as:

22 / 40

A gas expands from $\mathbf{3L}$ to $\mathbf{8L}$ at $\mathbf{2 \times}\mathbf{10}^{\mathbf{5\ }}\mathbf{Pa}$. The work done is:

23 / 40

Work done by a gas depends on:

24 / 40

A gas expands at constant pressure. Which statement is correct?

25 / 40

If pressure is constant and volume increases three times more than before, work done becomes:

26 / 40

A piston moves outward because gas pressure pushes it. The gas is:

27 / 40

The sign convention for work done by gas during expansion is usually:

28 / 40

A gas has pressure $\mathbf{4 \times}\mathbf{10}^{\mathbf{4}}\mathbf{\ Pa}$ and expands by $\mathbf{0.5\ m}^{\mathbf{3}}$. Work done equals:

29 / 40

If a gas expands at zero pressure, work done is:

30 / 40

The physical meaning of $\mathbf{p\mathrm{\Delta}V}$ is:

31 / 40

A gas expands at constant pressure from $\mathbf{10\ m}^{\mathbf{3}}$ to $\mathbf{12\ m}^{\mathbf{3}}$. If $\mathbf{p = 500\ Pa}$, work done is:

32 / 40

Which graph gives the work done during constant pressure expansion?

33 / 40

A negative value of work done by gas indicates:

34 / 40

The equation $\mathbf{W = p\mathrm{\Delta}V}$ is an application of:

35 / 40

A gas absorbs heat and expands at constant pressure. Some energy is used for:

36 / 40

The unit conversion needed when volume is given in liters is:

37 / 40

The work done by gas at constant pressure is maximum when:

38 / 40

The work done by a gas increases if:

39 / 40

If $\mathbf{W = 1000\ J}$ and $\mathbf{\mathrm{\Delta}V =}\mathbf{0.5\ m}^{\mathbf{3}}$, pressure is:

40 / 40

The equation $\mathbf{W = p\mathrm{\Delta}V}$ shows that work done is:

Your score is

0%

9th class objective books