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Physics Chapter 1 : Topic 2
Dimensional Homogeneity
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A physical equation is said to be dimensionally homogeneous if:
Reasoning: A dimensionally homogeneous equation has identical dimensions on both sides.
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Which of the following equations is dimensionally correct?
Reasoning: All terms have dimensions of velocity $\mathbf{\lbrack}\mathbf{L\ T}^{\mathbf{- 1}}\mathbf{\rbrack}$.
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The equation $\mathbf{s = ut +}$ $\frac{\mathbf{1}}{\mathbf{2}}\mathbf{at}^{\mathbf{2}}$ is dimensionally correct because:
Reasoning: $\mathbf{ut}$ and $\mathbf{at}^{\mathbf{2}}$ both have dimensions $\mathbf{\lbrack L\rbrack}$.
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Which equation is dimensionally incorrect?
Reasoning: Energy has dimensions $\left\lbrack \mathbf{M\ }\mathbf{L}^{\mathbf{2\ }}\mathbf{T}^{\mathbf{- 2}} \right\rbrack$, while $\mathbf{mv}$ has $\left\lbrack \mathbf{M\ L\ }\mathbf{T}^{\mathbf{- 1}} \right\rbrack$.
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The dimensions of $\mathbf{v}^{\mathbf{2}}$ are:
Reasoning: Squaring velocity gives $\left( \mathbf{L}\mathbf{T}^{\mathbf{- 1}} \right)^{\mathbf{2}}$.
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Which equation passes the dimensional test?
Reasoning: Every term has dimensions $\left\lbrack \mathbf{L}^{\mathbf{2\ }}\mathbf{T}^{\mathbf{- 2}} \right\rbrack$.
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In dimensional analysis, numerical constants such as $\mathbf{2}$, $\frac{\mathbf{1}}{\mathbf{2}}\mathbf{\ }$, and $\mathbf{\pi}$ are:
Reasoning: Pure numbers have no dimensions.
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Which quantity has dimensions $\left\lbrack \mathbf{L}\mathbf{T}^{\mathbf{- 2}} \right\rbrack$?
Reasoning: Acceleration $\mathbf{=}$ velocity / time
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If $\mathbf{F =}\mathbf{mv}^{\mathbf{2}}$, the equation is:
Reasoning: $\mathbf{mv}^{\mathbf{2}}$ has dimensions of energy, not force.
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Which equation is dimensionally valid?
Reasoning: Both terms have dimensions of length.
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The dimensions of force are:
Reasoning: Force $\mathbf{=}$ mass $\mathbf{\times}$ acceleration
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Reasoning: Work and time cannot be added due to different dimensions.
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If dimensions of LHS and RHS are different, then:
Reasoning: Dimensional mismatch proves the equation is wrong.
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Which quantity has dimensions $\left\lbrack \mathbf{M\ }\mathbf{L}^{\mathbf{2\ }}\mathbf{T}^{\mathbf{- 2}} \right\rbrack$?
Reasoning: Energy $\mathbf{=}$ force $\mathbf{\times \ }$distance
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The equation $\mathbf{T = 2\pi}$ $\sqrt{\frac{\mathbf{l}}{\mathbf{g}}}$ is dimensionally correct because:
Reasoning: $\mathbf{\lbrack L\rbrack\ /\ }\left\lbrack \mathbf{L}\mathbf{T}^{\mathbf{- 2}} \right\rbrack\mathbf{=}\left\lbrack \mathbf{T}^{\mathbf{2}} \right\rbrack$, square root gives $\mathbf{\lbrack T\rbrack}$.
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The dimensions of pressure are:
Reasoning: Pressure $\mathbf{=}$ Force / Area
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Which equation is dimensionally homogeneous?
Reasoning: Both sides have dimensions of force.
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The dimensions of momentum are:
Reasoning: Momentum $\mathbf{=}$ mass $\mathbf{\times \ }$velocity
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Which statement about dimensional analysis is correct?
Reasoning: It checks dimensional consistency only.
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The dimensions of $\mathbf{a}^{\mathbf{2\ }}\mathbf{t}^{\mathbf{2}}$ are:
Reasoning: $\left( \mathbf{L\ }\mathbf{T}^{\mathbf{- 2}} \right)^{\mathbf{2}}\mathbf{\ }\left( \mathbf{T}^{\mathbf{2}} \right)^{\mathbf{2}}\mathbf{=}\mathbf{L}^{\mathbf{2}}$
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An equation passes dimensional analysis. This means:
Reasoning: Dimensional correctness is necessary but not sufficient.
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Which equation is dimensionally wrong?
Reasoning: $\mathbf{mv}$ is momentum, not force.
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Dimensions of gravitational acceleration ‘$\mathbf{g}$’ are:
Reasoning: It is an acceleration.
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Which quantity has dimensions $\left\lbrack \mathbf{M\ }\mathbf{L}^{\mathbf{- 1\ }}\mathbf{T}^{\mathbf{- 2}} \right\rbrack$?
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If $\mathbf{E =}$ $\frac{\mathbf{1}}{\mathbf{2}}\mathbf{mv}$, then the equation is:
Reasoning: $\mathbf{RHS}$ has momentum dimensions, not energy.
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The dimensions of $\mathbf{P \times t\ (power \times time)}$ are:
Reasoning: Power $\mathbf{\times}$ time $\mathbf{=}$ energy
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Reasoning: All terms represent velocity.
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The dimensions of density are:
Reasoning: Density $\mathbf{=}$ mass / volume
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Which equation correctly relates dimensions?
Reasoning: $\left\lbrack \mathbf{M\ L\ }\mathbf{T}^{\mathbf{- 2}} \right\rbrack\mathbf{\lbrack L\rbrack =}\left\lbrack \mathbf{M\ }\mathbf{L}^{\mathbf{2}}\mathbf{\ }\mathbf{T}^{\mathbf{- 2}} \right\rbrack$
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Which of the following is a limitation of dimensional analysis?
Reasoning: Numerical factors are dimensionless and cannot be obtained through dimensional analysis.
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The equation $\mathbf{v = u + 2at}$ is dimensionally:
Reasoning: The factor $\mathbf{2}$ does notaffect dimensions.
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Which equation is dimensionally homogeneous but physically incorrect?
Reasoning: Dimensions match, but dimensional analysis cannot determine the required numerical factor $\left( \frac{\mathbf{1}}{\mathbf{2}} \right)$.
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Why is dimensional homogeneity important?
Reasoning: Homogeneity is a necessary condition for physical validity.
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Which quantity has dimensions $\left\lbrack \mathbf{L}^{\mathbf{2\ }}\mathbf{T}^{\mathbf{- 2}} \right\rbrack$?
Reasoning: $\frac{\mathbf{1}}{\mathbf{2}}\mathbf{m}\mathbf{v}^{\mathbf{2}}\mathbf{/m =}\mathbf{v}^{\mathbf{2}}\mathbf{/2}$, dimensions $\left\lbrack \mathbf{L}^{\mathbf{2\ }}\mathbf{T}^{\mathbf{- 2}} \right\rbrack$.
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If an equation contains terms with dimensions of length, length, and velocity, the equation is:
Reasoning: Quantities with different dimensions cannot be added together.
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