FBISE, NCP & NBF-aligned resources for Classes 9–12
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Math Domain A.1 : Topic 1
Essential Questions Across the Branches of Chemistry
1 / 18
Simplify: $\sqrt{a^3}$
Reasoning: $\sqrt{a^3}=(a^3)^{\frac{1}{2}}=a^{\frac{3}{2}}$
2 / 18
Which expression is equal to $a^{\frac{1}{2}}$?
Reasoning: $a^{\frac{1}{2}}=\sqrt{a}$
3 / 18
Simplify: $\sqrt{a^2b^4}$
Reasoning: $\sqrt{a^2}=a$ and $\sqrt{b^4}=b^2$, therefore $\sqrt{a^2b^4}=ab^2$
4 / 18
Simplify: $(a^3)^{\frac{2}{3}}$
Reasoning: $(a^m)^n=a^{mn}$
$(a^3)^{\frac{2}{3}}=a^{3\times\frac{2}{3}}=a^2$
5 / 18
Which is equivalent to $\sqrt[3]{a^6}$?
Reasoning: $\sqrt[3]{a^6}=a^{\frac{6}{3}}=a^2$
6 / 18
Simplify: $\frac{a^{\frac{5}{2}}}{a^{\frac{1}{2}}}$
Reasoning: $\frac{a^m}{a^n}=a^{m-n}$
$\frac{a^{\frac{5}{2}}}{a^{\frac{1}{2}}}=a^{\frac{5}{2}-\frac{1}{2}}=a^{\frac{4}{2}}=a^2$
7 / 18
Simplify: $a^{\frac{3}{2}}\times a^{\frac{1}{2}}$
Reasoning: $a^m\times a^n=a^{m+n}$
$a^{\frac{3}{2}}\times a^{\frac{1}{2}}=a^{\frac{4}{2}}=a^2$
8 / 18
Simplify: $\sqrt{49a^2}$
Reasoning: $\sqrt{49}=7$ and $\sqrt{a^2}=a$
Therefore $\sqrt{49a^2}=7a$
9 / 18
Which is correct?
Reasoning: Negative index means reciprocal.
$a^{-1}=\frac{1}{a}$
10 / 18
Simplify: $a^{\frac{1}{3}}\times a^{\frac{2}{3}}$
Reasoning: $a^{\frac{1}{3}}\times a^{\frac{2}{3}}=a^{\frac{3}{3}}=a$
11 / 18
Simplify: $\sqrt[4]{a^8}$
Reasoning: $\sqrt[4]{a^8}=a^{\frac{8}{4}}=a^2$
12 / 18
Simplify: $\frac{a^5}{a^2}$
Reasoning: $\frac{a^5}{a^2}=a^{5-2}=a^3$
13 / 18
Simplify: $a^{\frac{1}{2}}\times a^{\frac{3}{2}}$
Reasoning: $a^{\frac{1}{2}}\times a^{\frac{3}{2}}=a^{\frac{4}{2}}=a^2$
14 / 18
Which expression equals $\frac{1}{\sqrt{a}}$?
Reasoning: $\frac{1}{\sqrt{a}}=\frac{1}{a^{\frac{1}{2}}}=a^{-\frac{1}{2}}$
15 / 18
Simplify: $(a^2b^3)^{\frac{1}{2}}$
Reasoning: $(a^2b^3)^{\frac{1}{2}}=a^{2\times\frac{1}{2}}b^{3\times\frac{1}{2}}=ab^{\frac{3}{2}}$
16 / 18
Simplify: $\sqrt{a^4b^2}$
Reasoning: $\sqrt{a^4}=a^2$ and $\sqrt{b^2}=b$
Therefore $\sqrt{a^4b^2}=a^2b$
17 / 18
Simplify: $a^{\frac{2}{3}}\div a^{\frac{1}{3}}$
Reasoning: $a^{\frac{2}{3}}\div a^{\frac{1}{3}}=a^{\frac{2}{3}-\frac{1}{3}}=a^{\frac{1}{3}}$
18 / 18
Simplify: $\sqrt[3]{a^3b^6}$
Reasoning: $\sqrt[3]{a^3b^6}=a^{\frac{3}{3}}b^{\frac{6}{3}}=ab^2$
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